3.68 \(\int x^3 (1+x^2) (1+2 x^2+x^4)^5 \, dx\)

Optimal. Leaf size=23 \[ \frac {1}{26} \left (x^2+1\right )^{13}-\frac {1}{24} \left (x^2+1\right )^{12} \]

[Out]

-1/24*(x^2+1)^12+1/26*(x^2+1)^13

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Rubi [A]  time = 0.02, antiderivative size = 23, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {28, 266, 43} \[ \frac {1}{26} \left (x^2+1\right )^{13}-\frac {1}{24} \left (x^2+1\right )^{12} \]

Antiderivative was successfully verified.

[In]

Int[x^3*(1 + x^2)*(1 + 2*x^2 + x^4)^5,x]

[Out]

-(1 + x^2)^12/24 + (1 + x^2)^13/26

Rule 28

Int[(u_.)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Dist[1/c^p, Int[u*(b/2 + c*x^n)^(2*
p), x], x] /; FreeQ[{a, b, c, n}, x] && EqQ[n2, 2*n] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps

\begin {align*} \int x^3 \left (1+x^2\right ) \left (1+2 x^2+x^4\right )^5 \, dx &=\int x^3 \left (1+x^2\right )^{11} \, dx\\ &=\frac {1}{2} \operatorname {Subst}\left (\int x (1+x)^{11} \, dx,x,x^2\right )\\ &=\frac {1}{2} \operatorname {Subst}\left (\int \left (-(1+x)^{11}+(1+x)^{12}\right ) \, dx,x,x^2\right )\\ &=-\frac {1}{24} \left (1+x^2\right )^{12}+\frac {1}{26} \left (1+x^2\right )^{13}\\ \end {align*}

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Mathematica [B]  time = 0.00, size = 83, normalized size = 3.61 \[ \frac {x^{26}}{26}+\frac {11 x^{24}}{24}+\frac {5 x^{22}}{2}+\frac {33 x^{20}}{4}+\frac {55 x^{18}}{3}+\frac {231 x^{16}}{8}+33 x^{14}+\frac {55 x^{12}}{2}+\frac {33 x^{10}}{2}+\frac {55 x^8}{8}+\frac {11 x^6}{6}+\frac {x^4}{4} \]

Antiderivative was successfully verified.

[In]

Integrate[x^3*(1 + x^2)*(1 + 2*x^2 + x^4)^5,x]

[Out]

x^4/4 + (11*x^6)/6 + (55*x^8)/8 + (33*x^10)/2 + (55*x^12)/2 + 33*x^14 + (231*x^16)/8 + (55*x^18)/3 + (33*x^20)
/4 + (5*x^22)/2 + (11*x^24)/24 + x^26/26

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fricas [B]  time = 0.49, size = 61, normalized size = 2.65 \[ \frac {1}{26} x^{26} + \frac {11}{24} x^{24} + \frac {5}{2} x^{22} + \frac {33}{4} x^{20} + \frac {55}{3} x^{18} + \frac {231}{8} x^{16} + 33 x^{14} + \frac {55}{2} x^{12} + \frac {33}{2} x^{10} + \frac {55}{8} x^{8} + \frac {11}{6} x^{6} + \frac {1}{4} x^{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(x^2+1)*(x^4+2*x^2+1)^5,x, algorithm="fricas")

[Out]

1/26*x^26 + 11/24*x^24 + 5/2*x^22 + 33/4*x^20 + 55/3*x^18 + 231/8*x^16 + 33*x^14 + 55/2*x^12 + 33/2*x^10 + 55/
8*x^8 + 11/6*x^6 + 1/4*x^4

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giac [B]  time = 0.36, size = 61, normalized size = 2.65 \[ \frac {1}{26} \, x^{26} + \frac {11}{24} \, x^{24} + \frac {5}{2} \, x^{22} + \frac {33}{4} \, x^{20} + \frac {55}{3} \, x^{18} + \frac {231}{8} \, x^{16} + 33 \, x^{14} + \frac {55}{2} \, x^{12} + \frac {33}{2} \, x^{10} + \frac {55}{8} \, x^{8} + \frac {11}{6} \, x^{6} + \frac {1}{4} \, x^{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(x^2+1)*(x^4+2*x^2+1)^5,x, algorithm="giac")

[Out]

1/26*x^26 + 11/24*x^24 + 5/2*x^22 + 33/4*x^20 + 55/3*x^18 + 231/8*x^16 + 33*x^14 + 55/2*x^12 + 33/2*x^10 + 55/
8*x^8 + 11/6*x^6 + 1/4*x^4

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maple [B]  time = 0.00, size = 62, normalized size = 2.70 \[ \frac {1}{26} x^{26}+\frac {11}{24} x^{24}+\frac {5}{2} x^{22}+\frac {33}{4} x^{20}+\frac {55}{3} x^{18}+\frac {231}{8} x^{16}+33 x^{14}+\frac {55}{2} x^{12}+\frac {33}{2} x^{10}+\frac {55}{8} x^{8}+\frac {11}{6} x^{6}+\frac {1}{4} x^{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(x^2+1)*(x^4+2*x^2+1)^5,x)

[Out]

1/26*x^26+11/24*x^24+5/2*x^22+33/4*x^20+55/3*x^18+231/8*x^16+33*x^14+55/2*x^12+33/2*x^10+55/8*x^8+11/6*x^6+1/4
*x^4

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maxima [B]  time = 0.56, size = 61, normalized size = 2.65 \[ \frac {1}{26} \, x^{26} + \frac {11}{24} \, x^{24} + \frac {5}{2} \, x^{22} + \frac {33}{4} \, x^{20} + \frac {55}{3} \, x^{18} + \frac {231}{8} \, x^{16} + 33 \, x^{14} + \frac {55}{2} \, x^{12} + \frac {33}{2} \, x^{10} + \frac {55}{8} \, x^{8} + \frac {11}{6} \, x^{6} + \frac {1}{4} \, x^{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(x^2+1)*(x^4+2*x^2+1)^5,x, algorithm="maxima")

[Out]

1/26*x^26 + 11/24*x^24 + 5/2*x^22 + 33/4*x^20 + 55/3*x^18 + 231/8*x^16 + 33*x^14 + 55/2*x^12 + 33/2*x^10 + 55/
8*x^8 + 11/6*x^6 + 1/4*x^4

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mupad [B]  time = 0.06, size = 61, normalized size = 2.65 \[ \frac {x^{26}}{26}+\frac {11\,x^{24}}{24}+\frac {5\,x^{22}}{2}+\frac {33\,x^{20}}{4}+\frac {55\,x^{18}}{3}+\frac {231\,x^{16}}{8}+33\,x^{14}+\frac {55\,x^{12}}{2}+\frac {33\,x^{10}}{2}+\frac {55\,x^8}{8}+\frac {11\,x^6}{6}+\frac {x^4}{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(x^2 + 1)*(2*x^2 + x^4 + 1)^5,x)

[Out]

x^4/4 + (11*x^6)/6 + (55*x^8)/8 + (33*x^10)/2 + (55*x^12)/2 + 33*x^14 + (231*x^16)/8 + (55*x^18)/3 + (33*x^20)
/4 + (5*x^22)/2 + (11*x^24)/24 + x^26/26

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sympy [B]  time = 0.07, size = 75, normalized size = 3.26 \[ \frac {x^{26}}{26} + \frac {11 x^{24}}{24} + \frac {5 x^{22}}{2} + \frac {33 x^{20}}{4} + \frac {55 x^{18}}{3} + \frac {231 x^{16}}{8} + 33 x^{14} + \frac {55 x^{12}}{2} + \frac {33 x^{10}}{2} + \frac {55 x^{8}}{8} + \frac {11 x^{6}}{6} + \frac {x^{4}}{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*(x**2+1)*(x**4+2*x**2+1)**5,x)

[Out]

x**26/26 + 11*x**24/24 + 5*x**22/2 + 33*x**20/4 + 55*x**18/3 + 231*x**16/8 + 33*x**14 + 55*x**12/2 + 33*x**10/
2 + 55*x**8/8 + 11*x**6/6 + x**4/4

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